B. Com. I (OE) Practical No. 5: Graphical representation of data by using Ogive Curves and Locating Quartile Values.
Practical No. 5: Graphical representation of data by using Ogive Curves and Locating
Quartile Values.
Ogive Curve:
If we plot frequencies against the value,
we get the frequency curve. If instead of plotting frequencies we plot
cumulative frequencies to get an ogive curve.
In frequency curve we plot the
frequencies against the value of the variable but in An ogive curve is obtained
by plotting the cumulative frequency against the Class limits. There are two
type of cumulative frequencies
i. Less than cumulative
frequency
ii. Greater than cumulative
frequency
So we get two type of the ogive curve or
cumulative frequency curves as
i. Less than ogive or less
cumulative frequency curve
ii. Greater than ogive or
cumulative frequency curve
ii.
Less
than ogive or less cumulative frequency curve:
For Less than ogive curve
is we first add up the frequencies from top to bottom, (i.e. less than
cumulative frequencies) and then plotting the less than cumulative frequencies
against the upper limit of the corresponding class.
Note that the less than
ogive curve is started from the zero value on y-axis.
ii. Greater than ogive or
greater than cumulative frequency curve:
For Greater than
ogive curve is we first add up the frequencies from top bottom to top, (i.e.
greater than cumulative frequencies) and then plotting the greater than
cumulative frequencies against the lower limit of the corresponding class.
Note that the
greater than ogive curve is end at the zero value on y-axis.
e.g draw the ogive curve
for following data.
Marks |
No. of Students |
0-10 |
1 |
10-20 |
14 |
20-30 |
19 |
30-40 |
20 |
40-50 |
36 |
50-60 |
40 |
60-70 |
30 |
70-80 |
16 |
80-90 |
5 |
90-100 |
4 |
here we find the
cumulative frequencies.
Marks |
No. of Students |
Less than cumulative frequency |
Greater than cumulative frequency |
0-10 |
1 |
1 |
185 |
10-20 |
14 |
15 |
184 |
20-30 |
19 |
34 |
170 |
30-40 |
20 |
54 |
151 |
40-50 |
36 |
90 |
131 |
50-60 |
40 |
130 |
95 |
60-70 |
30 |
160 |
55 |
70-80 |
16 |
176 |
25 |
80-90 |
5 |
181 |
9 |
90-100 |
4 |
185 |
4 |
*Note that: here in ogive
curve we draw a dotted line. *
For Determining Median and Quartiles Graphically:
The median
is a measure of central tendency, along with the mean, used to describe the
typical or central value in a data set. The median is a statistical measure
that represents the middle value of a data set when it is arranged in ascending
or descending order.
It is the most
preferred measure of location for asymmetric distributions and is also
called a positional average. The median is defined as the value or
observation that lies at the center when all observations are arranged in order
of magnitude.
The median divides
the data set into two equal parts, with 50% of the data values below the
median and 50% above. It is particularly useful when dealing with skewed
distributions or data that contains outliers or extreme values,
since the median is not affected by such values, unlike the mean.
Calculation of Median (Ungrouped Data):
To calculate
the median, we first arrange the data in ascending or descending order.
The calculation of the median depends on the total number of observations
in the data set:
- If the number of observations is odd,
the median is the middle value.
Example:
Observations: 14, 20, 17, 18, 15
→ Arranged: 14, 15, 17, 18, 20 (arrange
the data in ascending or descending order)
→ Number of observations = 5 (odd) (if total number of observations is odd
there is one observation at the center hence the median value is the middle
observation e.g. if the observations are
14, 20, 17, 18, 15. then firstly we arranging in ascending order as 14, 15, 17,
18, 20. here total number of observation is 5 and it is odd then at the middle
only one value is median = 17.)
→ Median = 3rd value = 17
- If the number of observations is even,
the median is the average of the two middle values.
Example:
Observations: 20, 100, 25, 14, 16, 10
→ Arranged: 10, 14, 16, 20, 25, 100
→ Number of observations = 6 (even)
→ Middle values = 16 and 20
(i.e. if the total
number of observation is even then data set contain two value at
the middle then we take average of two middle value and consider as median.)
e.g. the observations are 20, 100, 25, 14, 16, 10. here total observations are
6 it is even then the arranging in ascending order as 10, 14, 16, 20, 25,
100 in this case at the middle two values 15 and 20 then we take its
average as (16+20)/2 = 18)
→ Median = (16 + 20) / 2 = 18
Even if we
change the last value (100) to 1000, the median remains the same:
Data: 10, 14,
16, 20, 25, 1000
→ Median = 18
This shows that
the median is not affected by extreme values, since it is a positional
average. It is widely used in various fields, including statistics,
economics, and the social sciences.
Median Formula :
Median = size of [(N+1)/2]th observation
Quartiles:
For determining median we divided data in
two equal parts.in same way we can divided whole data into four equal parts we
use quartiles. There are three quartiles first, second, third quartiles, second
quartile is median. It is clear that the data divided in to four equal parts
lie at the quarter, half and three quarters in way to arranging data into
ascending or descending order.
It can be given as
Q1 = size of [(N+1)/4]th
observation
Median =Q2 = size of
[(N+1)/2]th observation
Q3 = size of [3(N+1)/4]th
observation
The approximate value for continuous
distribution the formula is
Q1 = size of [N/4]th
observation
Median =Q2 = size of
[N/2]th observation
Q3 = size of [N/4]th
observation
Graphical Determination of Median and Quartiles (Using
Ogive):
To determine
the median and quartiles graphically, we use an ogive (cumulative
frequency curve).
Steps:
1.
First Prepare a
Ogive Curve
2.
To find the median
or Q2: Median and second Quartile are same.
Q2
o Calculate N/2 and locate this value on
the Y-axis.
o Draw a Parallel line (at y=N/2)
from this point to meet the ogive curve.
o From the intersection point on the
curve, draw a Perpendicular line to the X-axis.
o The point where the perpendicular line
meets the X-axis represents the value of the Median or Q2
3.
Similarly, for Q1:
o Calculate N/4 and locate this value on
the Y-axis
o Draw a Parallel line (at y=N/4)
from this point to meet the ogive curve.
o From the intersection point on the
curve, draw a Perpendicular line to the X-axis.
o The point where the perpendicular line
meets the X-axis represents the value of the First quartile (Q1)
4.
For Q3:
o Calculate 3N/4 and locate this value on
the Y-axis
o Draw a Parallel line (at y=3N/4)
from this point to meet the ogive curve.
o From the intersection point on the
curve, draw a Perpendicular line to the X-axis.
o The point where the perpendicular line
meets the X-axis represents the value of the third quartile (Q3)
e.g draw the ogive curve for following data.
Marks |
No. of Students |
0-10 |
1 |
10-20 |
14 |
20-30 |
19 |
30-40 |
20 |
40-50 |
36 |
50-60 |
40 |
60-70 |
30 |
70-80 |
16 |
80-90 |
5 |
90-100 |
4 |
here
we find the cumulative frequencies.
Marks |
No. of Students |
Less than cumulative frequency |
Greater than cumulative frequency |
0-10 |
1 |
1 |
185 |
10-20 |
14 |
15 |
184 |
20-30 |
19 |
34 |
170 |
30-40 |
20 |
54 |
151 |
40-50 |
36 |
90 |
131 |
50-60 |
40 |
130 |
95 |
60-70 |
30 |
160 |
55 |
70-80 |
16 |
176 |
25 |
80-90 |
5 |
181 |
9 |
90-100 |
4 |
185 |
4 |
The Quartile Value are determined by graphically
1.
To find the median
or Q2: Median and second Quartile are same.
Q2
o Calculate N/2 and locate this value on the Y-axis. OR (The two ogive curves are intercept at point. draw a perpendicular from this point to x-axis we get medina of given data. therefore we draw both ogive curves to determine the median.) here any one method used to determine the median using ogive curve.
o Draw a Parallel line (at y=N/2 at 92.5) from this point to meet the ogive
curve.
o From the intersection point on the
curve, draw a Perpendicular line to the X-axis.
o The point where the perpendicular line
meets the X-axis represents the value of the Median or Q2 = 50.1
2.
Similarly, for Q1:
o Calculate N/4 and locate this value on
the Y-axis
o Draw a Parallel line (at y=N/4 = 46.25)
from this point to meet the ogive curve.
o From the intersection point on the
curve, draw a Perpendicular line to the X-axis.
o The point where the perpendicular line
meets the X-axis represents the value of the First quartile (Q1) = 36
3.
For Q3:
o Calculate 3N/4 and locate this value on
the Y-axis
o Draw a Parallel line (at y=3N/4 =
138.75) from this point to meet the ogive curve.
o From the intersection point on the
curve, draw a Perpendicular line to the X-axis.
o The point where the perpendicular line
meets the X-axis represents the value of the third quartile (Q3) = 62
Therefore Q1 = 36, Q2 = 50.1 and Q3 = 62
Example for Practice.
B. Com. I(OE): Basic Statistics Practical
- I
Expt.
No. 5
Date: / / 2025
Title: Graphical
representation of data by using Ogive Curves and Locating Quartile Values.
Q.1
Draw less than ogive from the following data.
Age in Year |
20-24 |
25-29 |
30-34 |
35-39 |
40-44 |
45-49 |
50-54 |
55-59 |
No. of Workers |
7 |
12 |
17 |
25 |
65 |
40 |
27 |
10 |
Q.
2 Draw an Ogive curve corresponding to the following data and compute
quartiles.
Wages in Rs |
25-30 |
30-35 |
35-40 |
40-45 |
45-50 |
50-55 |
55-60 |
60-65 |
65-70 |
No. of workers |
10 |
13 |
20 |
22 |
24 |
27 |
25 |
11 |
9 |
Q.3
Draw two Ogive curve and find median.
Marks |
0-5 |
5-10 |
10-15 |
15-20 |
20-25 |
25-30 |
30-35 |
35-40 |
No. of Students |
2 |
10 |
18 |
25 |
37 |
21 |
14 |
7 |
Q.4 Draw an Ogive curve corresponding
to the following data and compute quartiles.
Salary in Rs |
0-100 |
100-200 |
200-300 |
300-400 |
400-500 |
No. of Persons |
130 |
120 |
105 |
110 |
100 |
Q.
5 Draw greater than ogive curve from the following data.
Class |
0-9 |
10-19 |
20-29 |
30-39 |
40-49 |
50-59 |
60-69 |
70-79 |
Frequency |
2 |
7 |
14 |
30 |
40 |
36 |
18 |
10 |
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